Re: [WebDNA] Text Variable in Search
This WebDNA talk-list message is from 2010
It keeps the original formatting.
numero = 105377
interpreted = N
texte = This is a multi-part message in MIME format.------=_NextPart_000_0021_01CB1080.7F18A150Content-Type: text/plain;charset="iso-8859-1"Content-Transfer-Encoding: quoted-printablecorrection (forgot an ampersand):[search db=3Dinc/content.db&geSKUdata=3D0&SKUtype=3Dnum&SKUsort=3D1]From: Dan Strong=20Sent: Sunday, June 20, 2010 1:54 PMTo: talk@webdna.us=20Subject: Re: [WebDNA] Text Variable in SearchFrom: sgbc cebu=20Sent: Sunday, June 20, 2010 1:29 PMTo: talk@webdna.us=20Subject: [WebDNA] Text Variable in SearchNot totally sure what you're trying to do, but your argument (ge) =requires that SKU is *greater than or equal to* 0, so you also need to =tell the search query to treat the SKU field as a number for this =search, otherwise it can't make a numerical comparison:[search db=3Dinc/content.db&geSKUdata=3D0&SKUtype=3DnumSKUsort=3D1] [founditems] [showif [url][Slideshow][/url]=3D[url]YES[/url]] [text]YES=3DRockU[/text] [/showif] [/founditems][/search][YES]Also, not sure why you double-bracketed [Slideshow], but I removed the =second set of brackets, and if there are more than one SKUs that are =greater than or equal to 0 then you're going to get the value for the =last record in the [founditems] loop.If you are just making an example for learning purposes then hopefully =my code will help your understanding, but if this is fr an actual =project, I'd want to know more about what you're trying to do before I =said my code was the best solution.=20-Dan----------------------------------------Had difficulty of pulling a text variable via a database.Please consider this code:=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D==3D=3D=3D=3D=3D=3D=3D=3D[text]YES=3DRockU[/text][search db=3Dinc/content.db&geSKUdata=3D0&SKUsort=3D1][founditems][[Slideshow]][/founditems][/search]=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D==3D=3D=3D=3D=3D=3D=3D=3DWhere [SlideShow] either will get a YES or a NO from database.The problem is when [SlideShow] tells "YES".It will appear "[Yes]" on the page instead of "Rocku"Thanks------=_NextPart_000_0021_01CB1080.7F18A150Content-Type: text/html;charset="iso-8859-1"Content-Transfer-Encoding: quoted-printable
correction (forgot an =ampersand):
[search=20db=3Dinc/content.db&geSKUdata=3D0&SKUtype=3Dnum&SKUsort=3D1]<=/FONT>
Sent: Sunday, June 20, 2010 1:54 PM
Subject: Re: [WebDNA] Text Variable in =Search
Sent: Sunday, June 20, 2010 1:29 PM
Subject: [WebDNA] Text Variable in Search
Not totally sure what you're trying to =do, but your=20argument (ge) requires that SKU is *greater than or equal to* 0, so you =also=20need to tell the search query to treat the SKU field as a number =for this=20search, otherwise it can't make a numerical comparison:
[search=20db=3Dinc/content.db&geSKUdata=3D0&SKUtype=3DnumSKUsort=3D1]
&n=bsp; [founditems]
[showif =[url][Slideshow][/url]=3D[url]YES[/url]]
&n=bsp;[text]YES=3DRockU[/text]
[/showif]
[/founditems]
[/search]
[YES]
Also, not sure why you double-bracketed =[Slideshow], but I removed the second set of brackets, and if there are =more=20than one SKUs that are greater than or equal to 0 then you're going to =get the=20value for the last record in the [founditems] loop.
If you are just making an example for =learning=20purposes then hopefully my code will help your understanding, but =if this=20is fr an actual project, I'd want to know more about what you're trying =to do=20before I said my code was the best solution.
-Dan
----------------------------------------
Had difficulty of pulling a text variable via a=20database.
Please consider this=20code:
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D==3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
[text]YES=3DRockU[/text]
[search=20db=3Dinc/content.db&geSKUdata=3D0&SKUsort=3D1]
[founditems]
[[Slideshow]]
[/founditems]
[/search]
=3D=3D=3D=3D=3D==3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D==3D=3D=3D
Where=20[SlideShow] either will get a YES or a NO from database.
The =problem is=20when [SlideShow] tells "YES".
It will appear "[Yes]" on the page =instead of=20"Rocku"
Thanks
------=_NextPart_000_0021_01CB1080.7F18A150--
Associated Messages, from the most recent to the oldest:
This is a multi-part message in MIME format.------=_NextPart_000_0021_01CB1080.7F18A150Content-Type: text/plain;charset="iso-8859-1"Content-Transfer-Encoding: quoted-printablecorrection (forgot an ampersand):[search db=3Dinc/content.db&geSKUdata=3D0&SKUtype=3Dnum&SKUsort=3D1]From: Dan Strong=20Sent: Sunday, June 20, 2010 1:54 PMTo: talk@webdna.us=20Subject: Re: [WebDNA] Text Variable in SearchFrom: sgbc cebu=20Sent: Sunday, June 20, 2010 1:29 PMTo: talk@webdna.us=20Subject: [WebDNA] Text Variable in SearchNot totally sure what you're trying to do, but your argument (ge) =requires that SKU is *greater than or equal to* 0, so you also need to =tell the search query to treat the SKU field as a number for this =search, otherwise it can't make a numerical comparison:[search db=3Dinc/content.db&geSKUdata=3D0&SKUtype=3DnumSKUsort=3D1] [founditems] [showif [url][Slideshow][/url]=3D[url]YES[/url]] [text]YES=3DRockU[/text] [/showif] [/founditems][/search][YES]Also, not sure why you double-bracketed [Slideshow], but I removed the =second set of brackets, and if there are more than one SKUs that are =greater than or equal to 0 then you're going to get the value for the =last record in the [founditems] loop.If you are just making an example for learning purposes then hopefully =my code will help your understanding, but if this is fr an actual =project, I'd want to know more about what you're trying to do before I =said my code was the best solution.=20-Dan----------------------------------------Had difficulty of pulling a text variable via a database.Please consider this code:=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D==3D=3D=3D=3D=3D=3D=3D=3D[text]YES=3DRockU[/text][search db=3Dinc/content.db&geSKUdata=3D0&SKUsort=3D1][founditems][[Slideshow]][/founditems][/search]=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D==3D=3D=3D=3D=3D=3D=3D=3DWhere [SlideShow] either will get a YES or a NO from database.The problem is when [SlideShow] tells "YES".It will appear "[Yes]" on the page instead of "Rocku"Thanks------=_NextPart_000_0021_01CB1080.7F18A150Content-Type: text/html;charset="iso-8859-1"Content-Transfer-Encoding: quoted-printablecorrection (forgot an =ampersand):
[search=20db=3Dinc/content.db&geSKUdata=3D0&SKUtype=3Dnum&SKUsort=3D1]<=/FONT>
Sent: Sunday, June 20, 2010 1:54 PM
Subject: Re: [WebDNA] Text Variable in =Search
Sent: Sunday, June 20, 2010 1:29 PM
Subject: [WebDNA] Text Variable in Search
Not totally sure what you're trying to =do, but your=20argument (ge) requires that SKU is *greater than or equal to* 0, so you =also=20need to tell the search query to treat the SKU field as a number =for this=20search, otherwise it can't make a numerical comparison:
[search=20db=3Dinc/content.db&geSKUdata=3D0&SKUtype=3DnumSKUsort=3D1]
&n=bsp;
[founditems] &n=bsp;
[text]YES=3DRockU[/text]
[/showif]
[/founditems]
[/search]
[YES]
Also, not sure why you double-bracketed =[Slideshow], but I removed the second set of brackets, and if there are =more=20than one SKUs that are greater than or equal to 0 then you're going to =get the=20value for the last record in the [founditems] loop.
If you are just making an example for =learning=20purposes then hopefully my code will help your understanding, but =if this=20is fr an actual project, I'd want to know more about what you're trying =to do=20before I said my code was the best solution.
-Dan
----------------------------------------
Had difficulty of pulling a text variable via a=20database.
Please consider this=20code:
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D==3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
[text]YES=3DRockU[/text]
[search=20db=3Dinc/content.db&geSKUdata=3D0&SKUsort=3D1]
[founditems]
[[Slideshow]]
[/founditems]
[/search]
=3D=3D=3D=3D=3D==3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D==3D=3D=3D
Where=20[SlideShow] either will get a YES or a NO from database.
The =problem is=20when [SlideShow] tells "YES".
It will appear "[Yes]" on the page =instead of=20"Rocku"
Thanks
------=_NextPart_000_0021_01CB1080.7F18A150--
"Dan Strong"
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