Re: [OT] Ratings comparison?
This WebDNA talk-list message is from 2003
It keeps the original formatting.
numero = 54971
interpreted = N
texte = [math]SCORE=([[shop]_Avg_Of_All_Reviews]*.7)+([[shop]_Times_Reviewed]*.3)[/math] [!]-- Percent... always=100... (Right now, Averages are worth 70% of the final score and Reviews are worth 30% . Adjust as needed, of course --[/!]Store A:---------AVG=8REV=1then [score]=5.9Store B:---------AVG=7REV=100then [score]=34.9Whattya think?-Dan------------------------------------------------------------http://www.StrongGraphicDesign.comhttp://www.SearchBoise.com(208) 319-0137 | Toll-free p/f 877-561-1656------------------------------------------------------------Haven't really thought it through... this could be slicker I suppose, but it would work, no?On Fri, 12 Dec 2003 15:06:40 -0800 Marc Kaiwi
wrote:>Hummm ... You might have something here ... okay thinking this through:>>Assume that: The total sum of all reviews divided by the number of total reviews = >[Avg_Of_All_Reviews] = 7>If shop_A has 1 review of 8 then [Shop_A_Avg] = 8>If shop_B has 100 reviews averaging 7 then [Shop_B_Avg] = 7>...>...>...>humm ...>...>Arrrggggg ... there's still know way to compare shop_a to shop_b!>>I'm still thinkin' ...... : c)>>Thanks,>>MK>>On Friday, December 12, 2003, at 02:46 PM, Gary Krockover wrote:>>>Wouldn't you want to do a total sum of all reviews / # of reviews >>(avg)? Maybe that's what you're doing already. Are you showing the >>number of reviews that each store has received? That would let the >>visitor weigh the review average.>>>>GK>>>>At 04:06 PM 12/12/2003, you wrote:>>>I'm writing a small program that allows visitors to "rate" different >>>shops from 1 to 10 (for example).>>>>>>My question is this:>>>>>>If one shop has a rating average of 8 but has only been "reviewed" a >>>few times and another shop has an average rating of 7 but has been >>>"reviewed" many times. Is there a way to fairly compare the two?>>>>>>I realize the higher number of reviews has less influence on the >>>average but produces a more accurate rating, but is there a way to >>>compare them?>>>>>>I think (I'm afraid) the answer is no?>>>>>>Anyone?>>>>>>Thanks again,>>>>>>>>>>>>Signed: Marc Kaiwi>>>>>>------------------------------------------------------------->>This message is sent to you because you are subscribed to>> the mailing list .>>To unsubscribe, E-mail to: >>To switch to the DIGEST mode, E-mail to >>>>Web Archive of this list is at: http://webdna.smithmicro.com/>>>>>Signed: Marc Kaiwi>>>------------------------------------------------------------->This message is sent to you because you are subscribed to> the mailing list .>To unsubscribe, E-mail to: >To switch to the DIGEST mode, E-mail to >Web Archive of this list is at: http://webdna.smithmicro.com/-------------------------------------------------------------This message is sent to you because you are subscribed to the mailing list .To unsubscribe, E-mail to: To switch to the DIGEST mode, E-mail to Web Archive of this list is at: http://webdna.smithmicro.com/
Associated Messages, from the most recent to the oldest:
[math]SCORE=([[shop]_Avg_Of_All_Reviews]*.7)+([[shop]_Times_Reviewed]*.3)[/math] [!]-- Percent... always=100... (Right now, Averages are worth 70% of the final score and Reviews are worth 30% . Adjust as needed, of course --[/!]Store A:---------AVG=8REV=1then [score]=5.9Store B:---------AVG=7REV=100then [score]=34.9Whattya think?-Dan------------------------------------------------------------http://www.StrongGraphicDesign.comhttp://www.SearchBoise.com(208) 319-0137 | Toll-free p/f 877-561-1656------------------------------------------------------------Haven't really thought it through... this could be slicker I suppose, but it would work, no?On Fri, 12 Dec 2003 15:06:40 -0800 Marc Kaiwi wrote:>Hummm ... You might have something here ... okay thinking this through:>>Assume that: The total sum of all reviews divided by the number of total reviews = >[Avg_Of_All_Reviews] = 7>If shop_A has 1 review of 8 then [Shop_A_Avg] = 8>If shop_B has 100 reviews averaging 7 then [Shop_B_Avg] = 7>...>...>...>humm ...>...>Arrrggggg ... there's still know way to compare shop_a to shop_b!>>I'm still thinkin' ...... : c)>>Thanks,>>MK>>On Friday, December 12, 2003, at 02:46 PM, Gary Krockover wrote:>>>Wouldn't you want to do a total sum of all reviews / # of reviews >>(avg)? Maybe that's what you're doing already. Are you showing the >>number of reviews that each store has received? That would let the >>visitor weigh the review average.>>>>GK>>>>At 04:06 PM 12/12/2003, you wrote:>>>I'm writing a small program that allows visitors to "rate" different >>>shops from 1 to 10 (for example).>>>>>>My question is this:>>>>>>If one shop has a rating average of 8 but has only been "reviewed" a >>>few times and another shop has an average rating of 7 but has been >>>"reviewed" many times. Is there a way to fairly compare the two?>>>>>>I realize the higher number of reviews has less influence on the >>>average but produces a more accurate rating, but is there a way to >>>compare them?>>>>>>I think (I'm afraid) the answer is no?>>>>>>Anyone?>>>>>>Thanks again,>>>>>>>>>>>>Signed: Marc Kaiwi>>>>>>------------------------------------------------------------->>This message is sent to you because you are subscribed to>> the mailing list .>>To unsubscribe, E-mail to: >>To switch to the DIGEST mode, E-mail to >>>>Web Archive of this list is at: http://webdna.smithmicro.com/>>>>>Signed: Marc Kaiwi>>>------------------------------------------------------------->This message is sent to you because you are subscribed to> the mailing list .>To unsubscribe, E-mail to: >To switch to the DIGEST mode, E-mail to >Web Archive of this list is at: http://webdna.smithmicro.com/-------------------------------------------------------------This message is sent to you because you are subscribed to the mailing list .To unsubscribe, E-mail to: To switch to the DIGEST mode, E-mail to Web Archive of this list is at: http://webdna.smithmicro.com/
"Dan Strong"
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